Consider a test that has a normal distribution, a mean of 100, and a s

QUESTION

Consider a test that has a normal distribution, a mean of 100, and a standard de-viation of 14. How high a score would a person need to be in the top ( a) 1% and ( b) 5%?

Using the above information and the 50% 34% 14% figures, what is the longest time to complete the word puzzle a person can have and still be in the bottom ( a) 2%, ( b) 16%, ( c) 50%, ( d) 84%, and ( e) 98%?
X ? N=(100,14^2). That mu=100 and =100 Let X1 be the score of the top 1% of the scorer P(X1>X)=0.01 So P(X1-100/14 > X-mu/)=0.01 That is¦

0.01 from normal statistical table (X1-100/14)=2.3263, Hence X1=132.5682 b) Same way for top 5 % the answer is 123.03

ANSWER:

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