E-Z Stop Fast Gas sold $10 957 worth of gasoline yesterday. Regular sold for $2.30 a gallon and

QUESTION

E-Z Stop Fast Gas sold $10,957 worth of gasoline yesterday. Regular sold for $2.30 a gallon, and premium sold for $2.55 a gallon. If the station sold 420 more gallons of regular than of premium:a. How many gallons of each type of gasoline were sold?Do not enter units in your answer.Premium:gallonsRegular:gallonsb. If the by Text-Enhance” in_hover=”” in_hdr=”” style=”color: rgb(1, 137, 197); text-decoration: underline !important; font-family: Arial, Helvetica, sans-serif !important; font-size: 10px !important; line-height: normal !important; background-color: transparent !important; border: none !important; display: inline-block !important; float: none !important; height: auto !important; margin: 0px !important; min-height: 0px !important; min-width: 0px !important; padding: 0px !important; vertical-align: baseline !important; width: auto !important;”>profit onregular gas is $0.18 per gallon and on premium is $0.20 per gallon, what was the stations total profit?$
Let x be gallons of regular sold Let y be gallons of premium sold Total revenue = 10,957 (given) Total revenue from regular sold = 2.3x Total revenue from premium sold = 2.55y Therefore, the equation becomes 2.3x + 2.55y = 10,957 ————— (1) When station sold 420 more gallons of regular than of premium, the equation becomes x y = 420 —————————-(2) Multiplying equation (2) by 2.3, we get 2.3x + 2.55y = 10,957 2.3x 2.3y = 966 (-) (+) (-) ————————— 4.85y = 9991 y = 2060 gallons Substituting the value of y in

n (2), we get x 2060 = 420 x = 2060 + 420 x = 2480 gallons Gallons of regular sold are 2480. Gallons of premium sold are2060. b. The profit on regular gas is $0.18 per gallon and the profit on premium gas is $0.20 per gallon. Therefore, 0.18x + 0.20y Substituting the value of x and y from part a. 0.18 (2480) + 0.20 (2060) 446.4 + 412 858.40 Hence, the total profit is $858.40.

ANSWER:

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